Help with Expressions.

[isdevilis]

Even though I know that the Bi-accumulator basically does this, I would like to figure out what is wrong with this expression. When I tryed to validate it, it said unexpected symbol at line one ; . Plus I would like to know what -> means anyway, becuase garrysmod.com's wiki did not explain that symbol. Thank you.
INPUT A B
OUTPUT Z

A==1 -> Z=1
B==1 -> Z=-1

[Acknar]

It is expecting a semicolon at the end of both of those line, because they are If statements. Which answers your second question, the -> indicates to E1 If A==1 then (->) Z=1

So...

A==1 -> Z=1;
B==1 -> Z=-1;

That should validate.

[isdevilis]

Well it works but I'm trying to get hoverballs to go up and down based upon the output of a adv. pod controller wired to an or any gate and another with a negate gate. In this instance
INPUT A B
OUTPUT Z

A==1 -> Z=1
B==1 -> Z=-1
it malfunctioned and when I used W it went up and didnt stop even when i let go of W. So I rewrote it so it looked like this.
INPUT A B
OUTPUT Z

A==1 -> Z=1;
B==1 -> Z=-1;
A==0 -> Z=0;
B==0 -> Z=0;
When I used this, it allowed me to validate it, but the hoverballs didnt move at all when i pressed W or S. Any suggestions?

[Bull]

A==1 -> Z=1;
B==1 -> Z=-1;
A==0 -> Z=0;
B==0 -> Z=0;
When you push A , B is still 0. So B==0->Z=0; Resets it to 0 again.

A==1 -> Z=1;
B==1 -> Z=-1;
!A&!B->Z=0;

That will work.
It says in human; If A is NOT pressed AND B is NOT pressed THEN Z=0

Ps. Thanks for adjusting your write-style. Highly appreciated.

[Asphid]

Personally, what I do for something like that is:

Inputs:  A B
Output: Z

Z = (A -B)

Where A and B are the two keys on the controller, and Z is wired to the first input of the hoverball.

That way, if nothing is hit, or both are hit, you get Z = 0. If you hit A it outputs 1, B outputs -1.


And yes, mad props on the improvement.

[isdevilis]

O lord I'm an idiot guys. I figured out what the problem was, it works perfectly now, but thanks for all the help and support.